If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15y^2-41y+14=0
a = 15; b = -41; c = +14;
Δ = b2-4ac
Δ = -412-4·15·14
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*15}=\frac{12}{30} =2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*15}=\frac{70}{30} =2+1/3 $
| 2x-3x-15=-2x+3x-21 | | 20p+5=18p-6 | | A=2+(-0,5b) | | 2t-5t=7 | | 5(s+1)=1 | | 4x^2+100=3 | | 38=-2x+13 | | 10x-8=4x+6 | | (3x+2)(x+1)=3x*x+17 | | 3=z+7/9 | | -13=5(1+4m)=12 | | 3x-10/2=2x-5/3 | | 8,4x=20 | | 2x+11x=6 | | 8;4x=20 | | 10t+6t=2 | | 3x-4=2x=2x+1-2x3x-4=2x=2x+1-2xx-4=1x-4+4=1-4x=3 | | 7×7=k+7 | | -2=-8+k/9 | | 2=-7+x/3 | | 7x+32=-17 | | 8p-4=6+5(p+9) | | -4=a+7/3 | | -11=-9+x/7 | | 5(9-t)=5 | | 22.68=3s+4.32 | | -10=-5p-5 | | 3x-4=2x=2x+1-2x | | -31.45=p-12 | | -1+v=-161 | | 18x-28=12x-4 | | 6x+18=9x-30 |